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0.75+18x-4.9x^2=0
a = -4.9; b = 18; c = +0.75;
Δ = b2-4ac
Δ = 182-4·(-4.9)·0.75
Δ = 338.7
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-\sqrt{338.7}}{2*-4.9}=\frac{-18-\sqrt{338.7}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+\sqrt{338.7}}{2*-4.9}=\frac{-18+\sqrt{338.7}}{-9.8} $
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